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HOMEWORK CHAPTER THREE
3.1) Equitangent crest vertical curve
520 Ft Long
L= 520 ft
G1= + 4%
G2= – 2.5 %
PVI= Station 340+00 at Elevation 1325 Ft
L1= L/2 = 520/2 = 260 ft
L2= L1 = 260 ft
- Station PVC = Station PVI – L1/100 = 340 + 00 – 260/100
= 340 + 00 – (2.6) =340 + 00 – (300 – 40)
= 340 + 00 – 300 + 40 = 337 + 40
- Station PVT = Station PVI + L2/100 = 340 + 00 + 2.6
= 340 + 00 (200 + 60) = 342 + 60
- Elevation PVC = Elevation PVI – G1* L/2*100 = 1325 – 4 * 520/200
=1325 – 10.4 = 1314.6 ft
- Elevation PVT = Elevation PVI + G2 * L/2*100
= 1325 + (-2.5 *520/200) = 1328.5 ft
- High Point
y = ax2 + bx + c and dy/dx = 2ax + b = 0 => x= – b/2a
b = G1 = 4 and,
a = (G1 – G2) / 2(L/100) = (- 2.5 – 4) / 2*2.5 = – 0.625
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